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x=2x^2-12x+23
We move all terms to the left:
x-(2x^2-12x+23)=0
We get rid of parentheses
-2x^2+x+12x-23=0
We add all the numbers together, and all the variables
-2x^2+13x-23=0
a = -2; b = 13; c = -23;
Δ = b2-4ac
Δ = 132-4·(-2)·(-23)
Δ = -15
Delta is less than zero, so there is no solution for the equation
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